KITE ISOSCELES TRIANGLE REGULAR HEXAGON RHOMBUS 2-12. The left circle could be “equilateral”, and the right could be “quadrilateral”. 57° , x = 31º b: Straight angle pair, supplementary, 2x 4x 150° = 180° , x = 5º 2-20.

a: Isosceles triangle 2 6 , parallelogram and square b: Equilateral triangle c: Parallelogram 2-11. C because the line of symmetry must pass through A (according to the marked sides of equal length) and these angles are on opposite sides of the line of symmetry.

a: 6x 6 b: 6x 6 = 78 , so x = 12 and the rectangle is 15 cm by 24 cm.

a: Yes, it is correct because the two angles make up a 90° angle. so one angle is 33 – 10 = 23° while the other is 2(33) 1 = 67°.

No – if the points are collinear then they will not form a triangle.

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If he left them outdoors, they will still be dead because it has not rained for 2 weeks, so he needed to water them once a week as well. a: y = –4 c: y = –2 4 b: y = 25 Core Connections Geometry Lesson 1.2.3 1-76. a: Area ≈ 16 square units b: Area ≈ 15 square units 1-67. c: There are 6 lines of symmetry, through opposite vertices and through the midpoints of opposite sides. (a) and (b) are perpendicular, while (b) and (c) are parallel. In order to belong to the intersection of both circles, a person would need to have long hair and study a lot for class. Carol: only inside circle #2, Bob: outside both circles, Pedro: only inside circle #1. Therefore, Sandy is more likely to select a shape with two sides that are parallel. Selected Answers b: They form a “Z.” 9 Lesson 2.1.3 2-31. a: 20 square units b: 2,600 square units; subtract the x- and y-coordinates to find the length of the two sides. a: 105° 75° 105° 75° 75° 105° 75° 105° b: 30° 70° 80° 80° 85° 95° 95° 85° 85° 95° 70° 30° 95° 85° 100° 80° 80° 100° 70° 110° 110° 70° 2-42. a: Yes, because the slopes are opposite reciprocals. Since a square has four sides and four right angles, it must be a rectangle. a: It should be a triangle with horizontal base of length 4 and vertical base of length 3. a = 118° , b = 118°, c = 32°, d = 32° b: x = 12° , m!

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